用 C语言完成：①设计一个员工的结构体，包含编号和薪水。②设计一个函数输入n个员工的信息。
③设计一个函数，找到n个员工薪水的平均值和中位数，并打印出薪水介于平均值和中位数之间的员工信息。

#include <stdio.h>
#include <stdlib.h>

typedef struct {
    int id;
    float salary;
} Employee;

void inputEmployees(Employee employees[], int n) {
    for (int i = 0; i < n; i++) {
        printf("请输入员工编号和薪水 (如：1 5000): ");
        scanf("%d %f", &employees[i].id, &employees[i].salary);
    }
}

float averageSalary(Employee employees[], int n) {
    float sum = 0;
    for (int i = 0; i < n; i++) {
        sum += employees[i].salary;
    }
    return sum / n;
}

int compare(const void *a, const void *b) {
    float diff = ((Employee *)a)->salary - ((Employee *)b)->salary;
    return (diff > 0) - (diff < 0);
}

float medianSalary(Employee employees[], int n) {
    qsort(employees, n, sizeof(Employee), compare);
    return (n % 2 != 0) ? employees[n/2].salary : (employees[n/2 - 1].salary + employees[n/2].salary) / 2;
}

void printEmployeesBetweenAverageAndMedian(Employee employees[], int n) {
    float average = averageSalary(employees, n);
    float median = medianSalary(employees, n);

    printf("平均薪水: %.2f\n", average);
    printf("中位数薪水: %.2f\n", median);

    printf("薪水介于平均值和中位数之间的员工信息：\n");
    for (int i = 0; i < n; i++) {
        if (employees[i].salary > average && employees[i].salary < median) {
            printf("员工编号: %d, 薪水: %.2f\n", employees[i].id, employees[i].salary);
        }
    }
}

int main() {
    int n;
    printf("请输入员工数量: ");
    scanf("%d", &n);

    Employee employees[n];

    inputEmployees(employees, n);
    printEmployeesBetweenAverageAndMedian(employees, n);

    return 0;
}

这个程序首先定义了一个员工结构体，包含员工编号和薪水。然后，它实现了几个函数：输入n个员工的信息、计算平均薪水、计算中位数薪水，以及打印薪水在平均值和中位数之间的员工信息。程序的主函数首先获取员工数量，然后调用这些函数完成任务。